Friday, 6 Mar 2026

Mastering HCF Competency Questions: Multiple Answer Strategies

Solving HCF Competency Questions with Multiple Answers

Competency-based questions (CBQs) on Highest Common Factor (HCF) often leave students confused, especially when multiple answers seem possible. This comprehensive guide breaks down a real exam-style problem to show you exactly how to approach these questions confidently. After analyzing an expert educator's video tutorial, I've distilled the key strategies that turn complex problems into solvable challenges.

Decoding the HCF Problem Structure

The sample question states: "HCF of k and 93 is 31, where k is a natural number. Which statements can be true?" with four options:

  1. k is a multiple of 31
  2. k is a multiple of 93
  3. k is an even number
  4. k is an odd number

Natural numbers (1,2,3...) always follow specific HCF rules. When HCF(k,93)=31, both numbers must share 31 as their highest common divisor. This immediately means k must contain 31 as a factor - a fundamental principle often overlooked in rushed exam attempts.

Step-by-Step Solution Breakdown

Let's examine each option systematically:

Option 1: k is a multiple of 31

  • Verification: If k=31×2=62, then HCF(62,93)=31 (since 62=2×31, 93=3×31)
  • Conclusion: Valid. Any multiple of 31 maintains 31 as common factor with 93.

Option 2: k is a multiple of 93

  • Verification: If k=93, then HCF(93,93)=93 ≠31
  • Critical insight: While 93 is a multiple of 31, the reverse isn't true. This confusion between factors and multiples causes most errors.
  • Conclusion: Invalid. HCF becomes 93 itself when k=93.

Option 3: k is even

  • Verification: k=62 (even) → HCF(62,93)=31
  • Conclusion: Valid. Even multiples of 31 work.

Option 4: k is odd

  • Verification: k=31 (odd) → HCF(31,93)=31
  • Conclusion: Valid. Odd multiples of 31 satisfy the condition.

Final Answer: Options 1,3 and 4 are correct.

Essential HCF Problem-Solving Framework

Based on this analysis, follow this proven approach for similar questions:

  1. Identify HCF condition: Write down "HCF(a,b)=c" clearly
  2. List factor relationships: c must be a factor of both a and b
  3. Test boundary cases: Try smallest possible values first (like c, 2c)
  4. Eliminate impossibilities: Check options that violate factor rules
  5. Verify with calculation: Never assume - compute HCF for each case

Common pitfalls to avoid:

  • Mistaking factors for multiples (as in Option 2)
  • Overlooking that HCF must divide both numbers
  • Forgetting that natural numbers include both odd/even

Advanced Preparation Strategy

Competency-based questions test conceptual clarity more than rote memorization. From the educator's teaching pattern, I recommend these actionable steps:

  1. Daily concept drilling: Solve 5 HCF problems focusing specifically on natural number properties
  2. Error journaling: Document why wrong options seem tempting (e.g., "Why did I think multiple of 93 would work?")
  3. Timed mock tests: Use platforms like Khan Academy's adaptive quizzes that simulate multi-answer CBQs

Recommended resources:

  • "Art of Problem Solving" by Richard Rusczyk (perfect for building logical reasoning)
  • Math Olympiad beginner workbooks (develop systematic approaches to complex problems)

Mastering these techniques transforms CBQs from intimidating to manageable. The key insight? Understanding why answers are correct matters more than memorizing solutions. Which HCF concept do you find most challenging when facing multiple-answer questions? Share your experience in the comments below.